If tan A = 1, sin B = 1√2, find the value of cos (A + B)
Answers
Answered by
0
Answer:
Step-by-step explanation:
TanA = 1
=> A = Tan⁻¹ (1) = 45°
SinB = 1/√2
=> B = Sin⁻¹(1/√2) = 45°
Thus Cos(A+B) = Cos(45 + 45) = Cos90° = 0.
Similar questions