If tan a = 12/5 then find the value of (Sin A + Cos A) x Sec A
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Answer:
Tan A = 12\5
Tan = P\B
P\B = 12\5
Let , P = 12k
B = 5k
H² = P² + B²
H² = (12k)² + (5k)²
H² = 144k² + 25k²
H² = 169k²
H = √169k²
H = 13k
Find : (Sin A + Cos A) x Sec A
(P\H + B\H) x H\B
(12k\13k + 5k\13k) x 13k\5k
17k\13k x 13k\5k
17k\5k
17\5 ( Ans )
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