If Tan A =2 then evaluate sec A . sin A +Tan 2 A- Cosec A
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Answered by
103
tanA=2
∵, sec²A-tan²A=1
or, sec²A=1+tan²A
or, sec²A=1+4
or, secA=√5
∴, cosA=1/secA=1/√5
Again, sin²A+cos²A=1
or, sin²A=1-cos²A
or, sin²A=1-1/5
or, sin²A=4/5
or, sinA=2/√5
∴, cosecA=1/sinA=√5/2
∴, secA.sinA+tan²A-cosecA
=√5.2/√5+(2)²-√5/2
=2+4-√5/2
=6-√5/2
∵, sec²A-tan²A=1
or, sec²A=1+tan²A
or, sec²A=1+4
or, secA=√5
∴, cosA=1/secA=1/√5
Again, sin²A+cos²A=1
or, sin²A=1-cos²A
or, sin²A=1-1/5
or, sin²A=4/5
or, sinA=2/√5
∴, cosecA=1/sinA=√5/2
∴, secA.sinA+tan²A-cosecA
=√5.2/√5+(2)²-√5/2
=2+4-√5/2
=6-√5/2
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15
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