Question

If tan A =3/4 and 0<Α<90⁰, then the value of Sin A. Cos A is *​

Answer 1

Sin A = 3/5 and Cos A = 4/5

Step-by-step explanation:

Tan A = 3/4

let, perpendicular = 3k and base = 4k [where k is constant]

So, Hypotenuse = $\sqrt{ {p}^{2} + {b}^{2} }$ $= \sqrt{ {(3k)}^{2} + {(4k)}^{2} } \\ = \sqrt{25k {}^{2} } \\ = 5k$

Therefore, Sin A = p/h = 3k/5k = 3/5

and Cos A = b/h = 4k/5k = 4/5

Answer 2

Answer:

Sin A = 3/5 and Cos A = 4/5

Tan A = 3/4

let, perpendicular = 3k and base = 4k [where k is constant]

So, Hypotenuse = \sqrt{ {p}^{2} + {b}^{2} }p2+b2 \begin{gathered}= \sqrt{ {(3k)}^{2} + {(4k)}^{2} } \\ = \sqrt{25k {}^{2} } \\ = 5k\end{gathered}=(3k)2+(4k)2=25k2=5k

Therefore, Sin A = p/h = 3k/5k = 3/5

and Cos A = b/h = 4k/5k = 4/

Step-by-step explanation:

I hope that help Samiksha ✔✔✔✔✌✌✌