Question

if tan a =5 by 13 find sin a+cosa​

Answer 1

Step-by-step explanation:

tan A=5/13

tanA =perpendicular /base

therefore, hypotenuse=?

H²=B²+P²

H=√B²+P²

H=√13²+5²=√194=13(approx)

now for SinA+CosA

SinA=perpendicular/hypotenuse

and CosA=base/hypotenuse

sinA=5/13

and CosA=13/13

therefore sinA+cosA=5/13+13/13=18/13