If tan A = a/b , PT a sin A - b cos A / a sin A + b cos A = a^2 - b^2 / a^2 + b^2
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Answer:
Let the two points be A(acosθ
1
,bsinθ
1
) and B(acosθ
2
,bsinθ
2
).
O (0,0) is origin.
Slope of OA=
acosθ
1
bsinθ
1
=
a
btanθ
1
Slope of OB=
acosθ
2
bsinθ
2
=
a
btanθ
2
Slope of OA× slope of OB=
a
2
b
2
tanθ
1
tanθ
2
=−1
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