Question

if tan A = a/b then what the value of bsinA - acosA/bsinA+acosA

Answer 1

हल-


$tanA \: = \frac{a}{b}$


$\frac{b \: sinA \: - a \: cosA }{b \: sinA \: + a \: cosA } \\ \\ = \frac{cosA \: (b \: tanA \: - a)}{cosA \: (b \: tanA \: + a)} \\ \\ = \frac{b \times \frac{a}{b} - a }{b \times \frac{a}{b} + a} \\ \\ = \frac{a - a}{a + a} \\ \\ = \frac{0}{2a} \\ \\ = 0$



Answer = 0

Answer 2

Step-by-step explanation:

tanA =a/b -----1)

from question .

cosA+ sinA/cosA -sinA

1 + tanA / 1 - tanA { dividing by cosA }

=] 1+ a/b

------------- [ From 1 ]

1 -a/b

=> a +b /b

---------------

a- b/b

=] ✓a+b /a-b Answer ...