If tan(A+B) =1/7 and tanA=1/3, find tanB
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Answer:
tan b= -2/11
Step-by-step explanation:
tan (a+b)=(tan a+tan b)/1-tana tanb
1/7=(1/3+tan b)/1-1/3 × tanb
take tan b =x
1/7=(1/3+x)/1-x/3
(1/7)(1-x/3)=1/3+x
(1/7)((3-x)/3)=(1+3x)/3
(3-x)/7 =1+3x
3-x=7+21x
-22x=4
x= -4/22=tanb
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