If tan ( A + B) = /3 and tan ( A - B) = 1//3, 0° < A + B <_90°, A> B then find the value of A and B
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tan(A+B)=√3....(1)
tan(A-B)=1/√3..(2)
__________________
A+B=60
A-B=30
__________
2A=90
_________
A=90/2=45
put A in equation (1)
A+B=60
45+B=60
B=60-45
B=15
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