Question

if tan [ A+ B ] =√3 AND TAN [A-B ] = 1 /√3 .THEN FIND THE VALUE OF A AND B

FASTEST WILL BE MARKED AS BRAINLIEST .

Answer 1

Solution:

Tan (A+B) = √3 ,..

Tan(A-B) = 1/√3

we know that ,

tan 60° = √3

&

tan 30° = 1/√3,.

so,

we can say,.

A+B = 60°, ...(i)

A - B = 30°,...(ii)

Hence,.

(i)+(ii) => (A + B)+(A - B) 60°+ 30°

=> 2A = 90°°

=> A = 45°,.

(ii) => A - B = 30°

=> 45 - B = 30°

=> -B = 30°-45°

=> B = 15°

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