Math, asked by joelkoshy82, 5 months ago

if tan(a+b)=√3 and tan(a-b)=1/√3, where A>B and A,B are acute angles. Find the values of A and B​

Answers

Answered by ayushmanalmiya
2

Answer:

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Step-by-step explanation:

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Answered by HetBrahmbhatt31
10

Answer:

A=45° and B=15°

Step-by-step explanation:

Given tan(A+B)=√3

⟹A+B=60∘⋯(1)

tan(A−B)= 1/√3

⟹A−B=30∘. ⋯(2)

(1)+(2)⟹2A=90∘

⟹A=45∘

Put A value in (1)

⟹B=60∘−45∘=15∘

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