if tan(a+b)=√3 and tan(a-b)=1/√3, where A>B and A,B are acute angles. Find the values of A and B
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Answer:
A=45° and B=15°
Step-by-step explanation:
Given tan(A+B)=√3
⟹A+B=60∘⋯(1)
tan(A−B)= 1/√3
⟹A−B=30∘. ⋯(2)
(1)+(2)⟹2A=90∘
⟹A=45∘
Put A value in (1)
⟹B=60∘−45∘=15∘
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