if tan(A+B)=3 and tan(A-B)=5 find the value of tan 2A
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Hi ,
tan ( A+ B ) = 3 ----( 1 )
tan (A - B ) = 5 ----( 2 )
tan 2A
= tan[ (A+ B ) + ( A - B ) ]
= [ tan(A+B)+tan(A-B)]/[1-tan(A+B)tan(A-B)]
= ( 3 + 5 ) / [ 1 - ( 3 × 5 ) ] from ( 1 ) & ( 2 )
= 8 / ( 1 - 15 )
= 8 / ( - 14 )
= - 4 / 7
I hope this helps you.
:)
tan ( A+ B ) = 3 ----( 1 )
tan (A - B ) = 5 ----( 2 )
tan 2A
= tan[ (A+ B ) + ( A - B ) ]
= [ tan(A+B)+tan(A-B)]/[1-tan(A+B)tan(A-B)]
= ( 3 + 5 ) / [ 1 - ( 3 × 5 ) ] from ( 1 ) & ( 2 )
= 8 / ( 1 - 15 )
= 8 / ( - 14 )
= - 4 / 7
I hope this helps you.
:)
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