If tan(A+B)=✓3 and tanA =1/✓3 , then sin2B is equals to ?
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Answer:
tan60°
Step-by-step explanation:
tan(A+B)=tanA+tanB
✓3 =1/✓3 +tanB
tanB =✓3- 1/✓3
B =2/✓3
sin^-1 B=2/✓3
sin B=✓3/2
sin 2B=✓3
sin 2B =tan 60°
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