If tan(A+B)=3 nd tan(A-B)=1/√3 where A > B. Find the value of A and B
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Tan [A + B] = √3
Tan [A + B] = Tan 600
[A + B] = 600
A + B = 60 -[1]
tan[ A - B] = 1/√3
Tan [A-B] = Tan 300
A-B = 30 -[2]
[1] - [2]
A + B = 60
A - B = 30
2 A = 90
A = 45
B = 30.
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