if tan (a+b) =√3,tan (a-b) =1/√3,a>b find A and B
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tan (a+b) =√3
As, tan 60 =√3
a+b=60..........(1)
tan(a-b) = 1/√3
As, tan 30 = 1/√3
a-b=30............(2)
Adding (1) and (2)
a+b=60
a-b=30
______
2a=90
a=90/2=45
Substitute a=45 in (2)
45-b=30
b=45-30=15
Therefore, a=45 and b= 15
Thank you...........
As, tan 60 =√3
a+b=60..........(1)
tan(a-b) = 1/√3
As, tan 30 = 1/√3
a-b=30............(2)
Adding (1) and (2)
a+b=60
a-b=30
______
2a=90
a=90/2=45
Substitute a=45 in (2)
45-b=30
b=45-30=15
Therefore, a=45 and b= 15
Thank you...........
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