Question

If tan (A+B) = √3, tan (A-B) = 1/√3, find tan A sin (A+B) + cos A tan (A-B)

Answer 1

Step-by-step explanation:

Given tan(A+B)=

3

⟹A+B=60

∘

⋯(1)

tan(A−B)=

3

1

⟹A−B=30

∘

⋯(2)

(1)+(2)⟹2A=90

∘

⟹A=45

∘

Put A value in (1)

⟹B=60

∘

−45

∘

=15

∘