Question

if tan(A-B)=7by24,tanA=4by3 wherea,b is acute then A+B=​

Answer 1

Answer:

Step-by-step explanation:

tan(A-B)=7/24

tanA=4/3

tan(A-B)=tanA-tanB/(1+tanAtanB)

7/24=(4/3)-tanB/(1+(4/3)tanB))

7(1+(4/3)tanB)=24*(4/3)-24tanB

7+28/3tanB=32-(24)tanB

25=(28/3+24)tanB

25=(100/3)tanB

tanB=3/4

tan(A+B)=tanA+tanB/(1-tanAtanB)

=(4/3)+(3/4)/(1-1)

=infinity

so A+B=90