Question

if tan a = b/a , so what is solution of a^2 cosec2a +b^2 sec 2a​

Answer 1

Answer:

tana=b/a=p/b

then by pythagoras theorem

=under root square asquare and b square

then AC=asquare +bsquare

then,

asquarecosec2a+bsquaresec2a

=then ,

we got asquare+bsquare+asquare+bsquare

then, we got

=2(asquare+bsquare)

Answer 2

Answer:

ok I don't want to answer because you already got your answer