Question

A ball is dropped from a height of 49 m. after 2s What will be the ratio between potential energy and kinetic energy? (Given g = 9.8 m / s2)​

Answer 1

Explanation:

v=u+at

v=0+9.8×2

v=19.6m/s

K.E=1/2 ×M× 19.6²

P.E=M×9.8×49

P.E:K.E=4:10=2:5