if tan a + b is equal to root 3 and 10 a minus b is equal to 1 by root 3
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Solution :
tan (a+b) = root3
We also know that, tan(pie/3) = root3
So, a+b = pie/3...............eqn.1
And also, 10a-b = 1/root3..............eqn.2
By solving eqn.1 and eqn.2 simultaneously,
We get a = (pie + root3)/33
b = (34root3 - pie)/33
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