Question

If tan???? = a/b , prove that asin???? - bcos???? / asin???? + bcos???? = a²-b² / a²+b²

Answer 1

Answer:

Tan θ = a/b.

sinθ/cosθ = a/b------(1).

lhs = (a sinθ- b cos θ)/(a sinθ + b cosθ).

= (asinθ/cosθ - bcosθ/cosθ)/(asinθ/cosθ+ bcosθ/cosθ).

dividing each term with cosθ.

=(asinθ/cosθ-b/1)/(asinθ/cosθ+b/1).

=(a*a/b-b/1)/(a*a/b +b/1).

[from (1)].

= (a^2-b^2)/(a^2+b^2).

=rhs.

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Answer 2

Step-by-step explanation:

upper answer is correct

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