Math, asked by samboy334, 11 months ago

If tan (a+b)=root 3 and tan (a-b)=1/root 3. Find the sin 2a and cos 6b

Answers

Answered by satyapriya34
2
I hope this will help you ..
Attachments:
Answered by balali91
1

Answer:

sin 2a=1

cos 6b=0

Step-by-step explanation:

tan(a+b) =√3→1

tan(a-b)=1/√3→2

from 1 and 2

a+b= 60°

a-b=30°

from these 2 equations we can find a=45° and b=15°

now sin(2*45)=sin(90)=1

and

cos(6*15)=cos(90)=0

hope it helps

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