If tan (a+b)=root 3 and tan (a-b)=1/root 3. Find the sin 2a and cos 6b
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Answer:
sin 2a=1
cos 6b=0
Step-by-step explanation:
tan(a+b) =√3→1
tan(a-b)=1/√3→2
from 1 and 2
a+b= 60°
a-b=30°
from these 2 equations we can find a=45° and b=15°
now sin(2*45)=sin(90)=1
and
cos(6*15)=cos(90)=0
hope it helps
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