Question

The area of rectangle is 5(y+3)(y^2-16).it's one side is 5(y^2-y-12).what is its other side

Answer 1

Let the other side be X
Then,


$5(y + 3)( {y}^{2} - 16) = 5( {y}^{2} - y - 12)x$
${y}^{3} + 3 {y}^{2} - 16y - 48 \div {y}^{2} - y - 12 = x$
$x = y + 4$

Answer 2

The other side is y+4

Step-by-step explanation:

Area of rectangle = 5(y+3)(y^2-16)

Length of one side = 5(y^2-y-12)

Other side =$\frac{Area}{Side}=\frac{5(y+3)(y^2-16)}{5(y^2-y-12)}$

                 =$\frac{5(y+3)(y^2-4^2)}{5(y^2-y-12)}$

                 =$\frac{5(y+3)(y-4)(y+4)}{5(y^2-y-12)}$

                 =$\frac{5(y^2-y-12)(y+4)}{5(y^2-y-12)}$

                  =$y+4$

Hence The other side is y+4

#Learn more:

The area of a rectangle is 392cm, find the length of the rectangle if base is twice its length

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