if tan(A-B)=tanA-tanB÷1+tanAtanB,then find the value of tan15°
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Hey !!!
tan15° = tan(45° - 30°)
According to formula
tan45° - tan30°
-----------------------
1 + tan45°*tan30°
1 - 1/√3
---------------
1 + 1×1/√3
√3- 1/√3
------------
√3 + 1/√3
tan15° = √3 -1 /√3 + 1 Answer
_____________________
Hope it helps you !!!
@Rajukumar111
tan15° = tan(45° - 30°)
According to formula
tan45° - tan30°
-----------------------
1 + tan45°*tan30°
1 - 1/√3
---------------
1 + 1×1/√3
√3- 1/√3
------------
√3 + 1/√3
tan15° = √3 -1 /√3 + 1 Answer
_____________________
Hope it helps you !!!
@Rajukumar111
golu281:
thnx
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