Question

If tan θ = a/b then asin????+bcos????/asin????-bcos???? is equal to
A. a+b/a-b
B. a²-b²/a²+b²
C. a+b/a-b
D.a-b/a+b

Answer 1

Answer:

ans b is correct...,..

Answer 2

B. a²+b²/a²-b²

Step-by-step explanation:

Given: tan θ = a/b

Find: asinθ + bcosθ / asinθ - bcosθ

Solution:

tan θ = a/b

Sinθ/ Cosθ = a/b ----------(1)

 Now asinθ + bcosθ / asinθ - bcosθ

= (asinθ + bcosθ)/Cosθ / (asinθ - bcosθ)/Cosθ

= (atanθ + b) / (atanθ -b)

= (a/b + b)(a/b - b)

= (a + b²)/b / (a²-b²)/b  

= (a + b²)/(a²-b²)

Option B is the answer.