Question

If tan∅=a/b then cos∅=​

Answer 1

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Ur answer

tantheta = a/b ,

AC=√a2+b2.

L.H.S=

asintheta-bcostheta/asintheta+bcostheta= a2-b2/a2+b2.

L.H.S.=

a(a/√a2+be) - b(b/√a2+b2)/a(a/√a2+be) + b(b/√a2+b2)

=a2 - b2/√a2 + b2/a2 + b2/√a2 + b2

=(√a2 + b2) will get canceled in numerator and denominator.

=a2-b2 /a2+b2

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