If tan a + cot a is equal to 2 find value of tan square a + cot square a
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tan a + cot a = 2
Squaring on both sides
(tan a + cot a)² = 2²
tan²a + cot²a + 2 × tan a × cot a
tan²a + cot²a + 2 × tan a ×1/tan a
tan²a + cot²a +2 = 4
tan²a + cot²a = 4 - 2
tan²a + cot²a = 2
Squaring on both sides
(tan a + cot a)² = 2²
tan²a + cot²a + 2 × tan a × cot a
tan²a + cot²a + 2 × tan a ×1/tan a
tan²a + cot²a +2 = 4
tan²a + cot²a = 4 - 2
tan²a + cot²a = 2
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[ Let a = ∅ ]
▶ Answer :-
→ tan²∅ + cot²∅ = 2 .
▶ Step-by-step explanation :- ----
➡ Given :-
→ tan ∅ + cot ∅ = 2 .
➡ To find :-
→ tan²∅ + cot²∅ .
We have ,
▶ Now,
→ To find :-
✔✔ Hence, it is solved ✅✅.
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