if tan A = cot B ,then the valunof (A
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Answer:
tanA= cotB
now, tanA = cot(90-A)
therefore ,cot(90-A)= cot B
90-A=B
90=A+B
or
A=90-B
Answered by
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Step-by-step explanation:
tanA = cotB
=> tanA = 1/tanB
=> 1 = tanAtanB
=> 1 - tanAtanB = 0 ----- *
tan(A+B) = [tanA + tanB]/[1 - tanAtanB]
By *, tan(A+B) = not defined
Thus, A+B = 90
Hope it helps
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