Question

If tan a is equal to x then find sec a

Answer 1

Tan a = x

As we know

[Tex]Tan{}^{2} a + 1 = sec{}^{2} a[/tex]

Put tan a=x

[Tex] x{}^{2}+1=sec{}^{2}a[/tex]

[Tex] \sqrt{x{}^{2}+1 } = sec \: a[/tex]

@skb

Answer 2

We have,
1+ tan²a= sec²a
1+x²= sec²a
±√(1+x²) = sec a
hence sec a= ±√(1+x²)