If tan A=
show that psinA- qcosA÷
psineS+ qcosA=p square-q square ÷psquare +q square
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Answer:
tan A = p/q
⇒ sin A / cos A = p/q
⇒ sin A = p/q cos A (p sin A - q cos A) / (p sin A + q cos A)
= (p × p/q cos A) - (q cos A) / (p × p/q cos A) + (q cos A)
= (p2/q) - (q) / (p2/q) + (q)
= (p2 - q2) / (p2 + q2)
∴ (p sin A - q cos A) / (p sin A + q cos A)
= (p2 - q2) / (p2 + q2).
Hope it helps you....
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