Question

If tan A = ½, tan B = 1/3 and tan (A+B) = tan +tan
÷ 1−tan tan
. Find (A + B). ​

Answer 1

Given: tan A = 1/3 and tan B = 1/2 tan (A + B) = tanA+tanB/ 1−tanA tanB

on substituting this values in RHS of the expression , we get

tanA+tanB÷1-tanA.tanB =

(1/3+1/2)÷(1-1/3×1/2)

(5/6)÷1-1/6

(5/6)÷(5/6)=1

tanA+tanB=1=45°

therefore , A+B =45°

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