Question

If tan A = ½ , tan B = ½, then value of A+B is:​

Answer 1

Given

tan A = 1/2, tan B = 1/2

tan(A + B) = (tan A + tan B)/(1 - tanA*tanB)

tan(A + B) = ((1/2)+(1/2))/((1-(1/2)(1/2))

tan(A + B) = 1/(1 - (1/4))

tan(A + B) = 1/(3/4)

tan(A + B) = 4/3

A + B = tan^(-1) (4/3) ——> Answer