If tan a = x/x+1
and tan B =1/2x+1
then a + B is equal to
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tan (A+B) = [tan (A) + tan (B)]/(1-tan (A)*tan (B))
putting given values,
tan (A+B)= (x/x+1 +1/2x+1)/(1-x/(x+1)(2x+1))
or,
tan (A+B) = (x(2x+1)+x+1)/[(x+1)*(2x+1)-x]
Value of both numerator and denominator on R.H.S. are equal hence,
tan (A+B) = 1
or
A+B = 45.
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