if tan alpha/2=1/√3 tan beta/2 then prove that cos beta = (2cos alpha-1) / (2- cos alpha).
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Alpha = @ & Beta = £
Tan @ = _/ 3 (given) where @ = 60°
Tan £ = 1 / _/ 3 where £ = 30°
Now , COT (@ + £)
(60° + 30°)
90•
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