Question

p2-2p - 15 plzz tell its a factorization quess............

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Answer 1

Correct question:

Factorise: p²- 2p - 15

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Solution:

In order to factorise a given expression, follow these steps:

• Check if you can take out common factor from all the terms.
• Regrouping the terms.
• Using identity (a+b)² = a²+ 2ab + b²
• Using identity (a-b)² = a²- 2ab + b²
• Using identity a²-b² = (a+b) (a-b)
• Splitting the middle term.

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Coming on to the question,

p²- 2p - 15

Here we will split the middle term.

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Steps for Splitting the middle term:

• Find product of first and last term.

$\sf \blue {1p²×15 = 15}$ We can ignore the variable.

• Write the factors of the product so obtained.

$\sf \blue {1×15}$

$\sf \blue {3×5}$

• Now find two numbers, whose product is that of first and last term and whose sum or difference is equal to the middle term.

$\sf \blue {3×5=15\ and\ 5-3 = 2}$

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Now,

p²- 2p - 15

p²- (5-3)p - 15

p² -5p +3p -15

Regrouping the terms,

(p² -5p) +(3p -15)

Taking out common from each group,

p(p-5) + 3(p-5)

$\boxed {\sf {\pink {(p+3) (p-5)}}}$

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Final answer:

The factorised form of p²-2p-15 is

(p+3) (p-5).