if tan alpha÷2=7 then 4sin alpha -3 cos alpha =?
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Answered by
3
Answer:
যদি tan alpha by2 7 হয় তাহলে 4 sin alpha - 3 cos alpha =???=
Answered by
0
Answer:
4sin α-3cos α = 4
Ans. 4
Step-by-step explanation:
tan α/2 = 7 => tan² α = 7²= 49
Sin α = (2tan α/2)/(1+tan² α)
cos α= (1-tan² α/2)/(1+tan² α/2)
Now,
4 sin α - 3 cos α
= 4{(2tan α/2)/(1+tan² α)} - 3{(1-tan² α/2)/(1+tan² α/2)}
=4{(2×7)/(1+49)} - 3{(1-49)/(1+49)}
=4(14/50) - 3 {(-48)/50}
= 56/50 + 144/50
= (56+144)/50
= 200/50
= 4
4sin α-3cos α = 4
Ans. 4
Step-by-step explanation:
tan α/2 = 7 => tan² α = 7²= 49
Sin α = (2tan α/2)/(1+tan² α)
cos α= (1-tan² α/2)/(1+tan² α/2)
Now,
4 sin α - 3 cos α
= 4{(2tan α/2)/(1+tan² α)} - 3{(1-tan² α/2)/(1+tan² α/2)}
=4{(2×7)/(1+49)} - 3{(1-49)/(1+49)}
=4(14/50) - 3 {(-48)/50}
= 56/50 + 144/50
= (56+144)/50
= 200/50
= 4
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