If tan alpha =n tan beta,sin alpha=m sin beta then prove that cos square alpha=m^2-1/n^2-1
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Answer:
Check the solution below.
Step-by-step explanation:
We have,
tan α = n tan β
⇒ tan β = tan α/n
⇒ cot β = n/tan α
sin α = m sin β
⇒ sin β = sin α/m
⇒ cosec β = m/sin α
Since
cosec2 β – cot2 β = 1
⇒ m2/sin2 α – n2/tan2 α = 1
⇒ m2/sin2 α – n2 cos2 α/sin2 α = 1
⇒ m2 – n2 cos2 α = sin2 α
⇒ m2 – n2 cos2 α = 1 – cos2 α
⇒ m2 – 1 = (n2 – 1) cos2 α
⇒ cos2 α = (m2 – 1)/(n2 – 1)
Hence proved.
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