IF tan AtanB = tan 45° so; Sin (A+B) = ?
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Answered by
0
We have
CosACosB- SinASinB =0
Cos (A+B) =0
Now, Sin (A +B) =square root of [1 - Cos ^2 (A+B)]
= 1
Answered by
3
the value of sin(A +B ) = ½
Step-by-step explanation:
- tanA + tanB = tan45°
- the value of Sin (A+B) .
tan is taken as common .
Now, value of sin ( A + B ) :-
we have find out the value of A + B = 45° .
So,
Hence, the value of sin(A +B ) = ½
Trigonometric tabe for some angles :-
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