If tan θ = cot (30° +θ ), find the value of θ.
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Answered by
5
Two angles are said to be complementary of their sum is equal to 90° .
θ & (90° - θ) are complementary angles
GIVEN:
tan θ = cot (30° + θ )
cot (90° - θ ) = cot (30° + θ )
[ cot ( 90° - θ) = tan θ ]
90° - θ = 30° + θ
θ + θ = 90 ° - 30 °
θ + θ = 60 °
2 θ = 60°
θ = 60 /2 = 30 °
θ = 30°
Hence , the value of θ is 30°.
HOPE THIS WILL HELP YOU...
θ & (90° - θ) are complementary angles
GIVEN:
tan θ = cot (30° + θ )
cot (90° - θ ) = cot (30° + θ )
[ cot ( 90° - θ) = tan θ ]
90° - θ = 30° + θ
θ + θ = 90 ° - 30 °
θ + θ = 60 °
2 θ = 60°
θ = 60 /2 = 30 °
θ = 30°
Hence , the value of θ is 30°.
HOPE THIS WILL HELP YOU...
Answered by
2
tan theeta = tan( 90 - ( 30+ theeta)
Tan theeta = tan(60 - theeta)
tan theeta = tan60 - tan theeta
2 tan theeta = tan 60
tan theeta = 30
= 1/√3...
Tan theeta = tan(60 - theeta)
tan theeta = tan60 - tan theeta
2 tan theeta = tan 60
tan theeta = 30
= 1/√3...
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