If ( tan θ + cot θ) = 5 then ( tan^2 θ + cot^2 θ) = ? (a) 27 (b) 25 (c) 24 (d) 23
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(tan A+ cot A ) = 5 squaring both side
(tanA + cot A )^2 = 25
tan^2A + cot^2A + tan A cot A = 25
tan^2A + cot ^2A = 25 - 2
= 23 Ans
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(tanA + cot A )^2 = 25
tan^2A + cot^2A + tan A cot A = 25
tan^2A + cot ^2A = 25 - 2
= 23 Ans
don't forget to mark as brainliest. .
also follow me for more accurate answers. .
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