if tan O=20/21,find sin O and cos O
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Tanθ = 20/21
so, sinθ =20/29
cosθ = 21/29
now,
(1-sinθ+cosθ)/(1+sinθ + cosθ)
putting the values,
[1 - (20/29)+(21/29)]/[1 +(20/29)+(21/29)]
=(29-20+21)/(29+20+21)
=30/70
=3/7
so, sinθ =20/29
cosθ = 21/29
now,
(1-sinθ+cosθ)/(1+sinθ + cosθ)
putting the values,
[1 - (20/29)+(21/29)]/[1 +(20/29)+(21/29)]
=(29-20+21)/(29+20+21)
=30/70
=3/7
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