Question

If
tan o+coto=5, find the value of
tan ²0+ cot²0​

Answer 1

Solution:-

Given,

tanθ+cotθ=5

Now squaring both sides we get,

$⇒\;{\sf{(tan θ+cot θ)² = (5)²}}$

$⇒\;{\sf{(tan²θ+cot²θ+2.tanθ.cotθ) = 25}}$

$⇒\;{\sf{tan²θ+cot²θ=25−2}}$

✯ $\blue{\bold{tanθ.cotθ=1}}$

$\Large{\bold{⇒\;tan²θ+cot²θ = \red{23}.}}$

Hope It Helps You ✌️

Answer 2

Step-by-step explanation:

Given,

tanθ+cotθ=5

Now squaring both sides we get,

Answer

⇒$\;{\sf{(tan θ+cot θ)² = (5)²}}$

⇒$\;{\sf{(tan²θ+cot²θ+2.tanθ.cotθ) = 25}}$

⇒$\;{\sf{tan²θ+cot²θ=25−2}}$

${\bold{tanθ.cotθ=1}}$

$\Large{\bold{⇒\;tan²θ+cot²θ = \red{23}.}}$