Question

if tan square a = 1 + 2 tan square b, prove cos square b = 2 cos square a​

Answer 1

$\huge\tt\blue{Answer:-}$

${tan}^{2} A = 1 + 2 {tan}^{2} B \\ = > {sec}^{2} A - 1 = 1 + 2( {sec}^{2} B - 1) \\ = > {sec}^{2} A = 1 + 1 + 2 {sec}^{2} B - 2 \\ = > {sec}^{2} A= 2 {sec}^{2} B - 2 + 2 \\ = > \frac{1}{ {cos}^{2} A} = 2 \times \frac{1}{ {cos}^{2} B} \\ = > \frac{ {cos}^{2} B}{ {cos}^{2}A } = 2 \\ = > {cos}^{2} B = 2 {cos}^{2} A$

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Answer 2

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Step-by-step explanation:

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