Math, asked by pe5ddysharmaa, 1 year ago

If tan teta + cot teta = 2 then tan^teta + cot^teta = ?

Answers

Answered by swapy2911

tanФ + cotФ = 2
(tanФ + cotФ)^2 = 2^2
tan^2Ф + 2tanФ * cotФ + cot^2Ф = 4
tan^2Ф + 2 + cot^2Ф = 4 ( as tanФ = 1/cotФ)
tan^2Ф + tan^2Ф = 2
similarly
tan^4Ф + cot^2Ф = 2
similarly
tan^2nФ + cot^2nФ (for any integer n) = 2
pls mark as brainliest

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