If tan tetha = 1/root3 then evaluate cosec^tetha- sec^ tetha/ cosec^tetha+ sec^tetha
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We have-
By Pythagoras theorem
Right angle triangle
Triangle ABC
AB=1
BC=Root3
AC=?
AC=AB +BC
AC=1+root3
AC=1square+root3 square
AC=1+3
AC=root4
AC=2
Put the value in equation-
Cosec theta-Sec theta/Cosec theta+Sec theta
Hypotenuse/ Base +Base /Hypotenuse
Hypotenuse /Base- Base /Hypotenuse.
By Pythagoras theorem
Right angle triangle
Triangle ABC
AB=1
BC=Root3
AC=?
AC=AB +BC
AC=1+root3
AC=1square+root3 square
AC=1+3
AC=root4
AC=2
Put the value in equation-
Cosec theta-Sec theta/Cosec theta+Sec theta
Hypotenuse/ Base +Base /Hypotenuse
Hypotenuse /Base- Base /Hypotenuse.
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