If tan theeta a-b/a+b , find the value of sin theeta
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so given height of a right angle triangle = a - b
given base of a right angle triangle = a +b
use Pythagoras theorem we get
hypotenuse = √{(a - b)² + (a + b)²}
= √{2(a² + b²)}
so sin θ=
(a - b)/√{2(a² + b²)}
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