If tan theta = 1/√3 , then evaluate ( cosec^2 theta - sec^2 theta / cosec^2 theta + sec^2 theta ) .
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59
tan∅ = 1/√3
We know, tan30 = 1/√3
tan∅ = tan 30°
∅ = 30°
××××××××××××××××××
(cosec²∅-sec²∅)÷(cosec²∅+sec²∅)
(cosec²30-sec²30)÷(cosec²30+sec²30)
[ (2)² - (2/√3)²] ÷ [ (2)² + (2/√3)²]
=> [ 4 - 4/3] ÷ [ 4+ 4/3]
=> [ (12 - 4)/3] ÷ [ (4 + 12)/3]
=> 8 ÷ 16
=> 1/2
I hope this will help you
(-:
We know, tan30 = 1/√3
tan∅ = tan 30°
∅ = 30°
××××××××××××××××××
(cosec²∅-sec²∅)÷(cosec²∅+sec²∅)
(cosec²30-sec²30)÷(cosec²30+sec²30)
[ (2)² - (2/√3)²] ÷ [ (2)² + (2/√3)²]
=> [ 4 - 4/3] ÷ [ 4+ 4/3]
=> [ (12 - 4)/3] ÷ [ (4 + 12)/3]
=> 8 ÷ 16
=> 1/2
I hope this will help you
(-:
abhi569:
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21
Answer: 1/2
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