If tan theta + 1/ tan theta =2 , the find the value of cot square theta + 1/cot square theta
Answers
Answered by
19
Given that,
tanθ + 1/tanθ = 2
or, 1/cotθ + cotθ = 2
=> cotθ + 1/cotθ = 2
Here,
tanθ = 1/cotθ
1/cotθ = tanθ
#
Answered by
17
Heya !!
Tan ¢ + 1/Tan¢ = 2
1/Cot ¢ + Cot¢ = 2
Cot¢ + 1/Cot¢ = 2
Squaring both sides ,
( Cot¢ + 1/Cot¢ )² = (2)²
Cot²¢ + 1/Cot²¢ + 2× Cot¢×1/Cot¢ = 4
Cot²¢ + 1/Cot²¢ = 4 - 2
Cot²¢ + 1/Cot²¢ = 2 .
Hope it will help you :-)
Tan ¢ + 1/Tan¢ = 2
1/Cot ¢ + Cot¢ = 2
Cot¢ + 1/Cot¢ = 2
Squaring both sides ,
( Cot¢ + 1/Cot¢ )² = (2)²
Cot²¢ + 1/Cot²¢ + 2× Cot¢×1/Cot¢ = 4
Cot²¢ + 1/Cot²¢ = 4 - 2
Cot²¢ + 1/Cot²¢ = 2 .
Hope it will help you :-)
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