Question

If tan theta =12/3 find 2 sin theta × cos theta /cos square theta -sin square theta​

Answer 1

Ans- p/b=12/3

h=

$\sqrt{313}$

$2 \sin \alpha \times \cos \alpha \div \cos {}^{2} \alpha - \sin {}^{2} \alpha$

2× p/h×b/h by 1-sin sq alpha - sin sq alpha

$2 \times 12 \div \sqrt{313 } \times 13 \div \sqrt{313} \div 1 - 2 \times 12 { \div \sqrt{313} }^{2}$

312/313-288

=312/25