If tan theta=4/3 find the values of cos^2 theta
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tan thita =4/3=perpendicular/base
so perpendicular=4k
base=3k.
hypotenuse=k√(4^2+3^2)=5k
so cos thita =b/h=3k/5k=3/5
cos^2 thita =(3/5)^2=9/25. Answer
so perpendicular=4k
base=3k.
hypotenuse=k√(4^2+3^2)=5k
so cos thita =b/h=3k/5k=3/5
cos^2 thita =(3/5)^2=9/25. Answer
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